# MAT183 CALCULUS I

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Application of Differentiation. Three paintbrushes with paint on the tips.

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We are really grateful because we manage to complete this video presentation within the given time by our lecturer , Madam Liyana . This assignment is impossible to be done without the amazing cooperation abd effort of our group members Mirrah Syafiah , Alia Athirah , and Fazizatul Hana. We also sincerely thank our lecturer of Calculus 1, Madam Liyana for the guidance and willingness to help us in what we are lacking when completing this assignment and surely for teaching us this course. Last but not least, we would like to express our gratitude to our family members who keep encouraging us all the this time..

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Meet out team!. Presenter 1. Presenter 3. Name :.

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Introduction. Differentiation is the process of finding the derivative or the rate of change of the function. The practical method of differentiation is simple, using knowledge of three basic derivatives, four operational rules, and how to operate a function. It can be done by algebraic operations..

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For the other operational rules, which is product rules. It provides a way to differentiate compound functions. The chain rule states that the derivative of a composite function is given by a product, as D(f(g(x))) = Df(g(x)).

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Problem Statement. A SPHERICAL BALLOON IS BEING INFLATED AT THE RATE OF 8 CM3/SEC.

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Problem Solution ;. dv/ dt =8 cm3 /sec ( dr )/ dt =? cm3 /sec.

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Conclusion. Based on the problem statement there is a spherical balloon being inflated at the rate of 8cm3 /sec.as we know the basic formula when we get any question about sphere are.

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As we are asked to determine the rate at which the radius of the inflated balloon is changing when the radius is 10cm.

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So we have to apply differentiation in our problem-solving. based on our problem-solving, we can see that the volume of the sphere change at a rate of 8cm3 /sec. Secondly, we have to differentiate the volume of the sphere formula to get the dv/ dr and it will be 4πr^2. after we have the dv/ dr we can inverse it to be dr /dv which we need to use in the formula to find the rate at which the radius of the balloon is changing when the radius is 10cm.

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A lamp shining light onto a desk. A cat. Thank You For Watching!.