TILE LAYING MACHINE

[Audio] TILE LAYING MACHINE. Need Statement. Laying of tiles is a laborious work. Design a solution to make it more feasible and less time consuming..

[Audio] Problem Definition. A tile laying machine is an instrument which is used to flatten sand and lay various types of tiles on a designated floor. These types of bots are programmable and are able to dispense required material when necessary..

[Audio] Objectives. User friendly. Strong framework/Durable. Bot should be as light as possible. Bot should be portable. Sturdy material. Aesthetically pleasing. Good gripped tire. Problem definition 1.1. Design a user friendly tile laying machine, that is light and portable. The bot must be made up of sturdy material and have a strong framework to support the entire system. It should have a good gripped tire in order to facilitate it's movement. It should also be aesthetically pleasing to the eyes of an observer..

[Audio] Constraints. Problem definition 1.2. Design a user friendly tile laying machine, that is light and portable. The bot must be made up of sturdy material and have a strong framework to support the entire system. It should have a good gripped tire in order to facilitate it's movement. It should also be aesthetically pleasing to the eyes of an observer. The bot should be 3x3x3 feet in dimensions and should be built within a budget of 5000 INR within a time duration of 2 months. It should be able to hold 10 tiles of size 1.5x.5 feet of standard thickness..

[Audio] Problem definition 1.3.Design a user friendly tile laying machine, that is light and portable. The bot must be made up of sturdy material and have a strong framework to support the entire system. It should have a good gripped tire in order to facilitate it's movement. It should also be aesthetically pleasing to the eyes of an observer. The bot should be 3x3x3 feet in dimensions and should be built within a budget of 5000 INR within a time duration of 2 months. It should be able to hold 10 tiles of size 1x1 feet of standard thickness. The bot should have a provision to turn on and off with a switch and should have an indicator, which shows that the bot is operational. It should be able to store and lay tiles while the bot is in motion..

QnA Table:.

[Audio] Concept generation. Concept generation:. ESTABLISHING FUNCTIONS :.

[Audio] Function Tree. Function Tree:. Screenshot (158).

[Audio] Morphological chart:. Morphological chart:.

Crankshaft Pushing of the tiles 3 on to conveyer belt.

00 5 6 Switching on the bot Storage of tiles Vertical columns on off switch Box with a small gap at bottom toggle switch an open container with no roof for manual feeding of tiles mobile controlled Plastic container with sliding lid.

7 8 Conversion of Electrical energy to Mechanical Energy Tile dropping BLDC Conveyer belt Suction cups.

[Audio] Generated concepts:. Generated Concepts:.

[Audio] PUGH Chart.. CONCEPT EVALUATION AND ARCHITECTURE.

[Audio] Justification of scores. Justification of scores:.

[Audio] Justification of scores. Justification of scores:.

[Audio] Concept 1 and 2. Concept 1 and 2:. concept 1.

[Audio] Concept 3 and 4. Concept 3 and 4:. cocept 4.

[Audio] Finalized design. Finalized Design:. 140! u! d.

Sub-System list and Function Clustering:. Screenshot (159).

Interaction between sub-systems:. Flattening of Sand Spatial Data Material Storing Tiles Subsystem Laying Tiles Subsystem Movement Of Bot Subsystem Yes.

MOTOR AND ADAPTOR SELECTION:. MOTOR SELECTION: Torque for Belt Drive: Volume of upper portion = (0.020+0.005)m^3 = 0.025m^3 Density of bot above belt drive = 200 kg/m^3 Mass of Bot above the bet drive = Density x Volume = 0.025 x 200 kg/m^3 = 5kg Mass of Motors(4 motors) = 1 kg. Mass of(load) and other materials = (0.1+0.4) = 0.5 kg. Total mass = 5.5 kg. Coefficient of friction = 0.7 Force(Horizontal) = µ x mass x gravity.(µ = 0.7, mass = 5 kg, gravity = 9.81 m/s^2) Force = 0.7 x 5.5 x 9.81 = 34.335 N. Torque = Force x perpendicular distance.(Force = 34.335 N, perpendicular distance = 2 cm) Torque = 34.335 x 2 = 68.67 N-cm. Torque = 7.63 kg-cm. Torque with (FOS = Factor of safety =1.5) = 10.5 kg-cm. As torque is divided amidst two motors, so the torque for each motor will be = 5.2 kg-cm..

Torque for Conveyer Belt: Volume of Conveyer Belt = 0.003m^3. Volume of rod and middle plank(2 rods) = 0.00059m^3. Total Volume = 0.00359m^3 Density of belt drive = 500 kg/m^3 Mass of motor = 0.3 k*g. Mass of load = 0.1kg Mass of belt drive = 1.695 kg. Total mass = 1.795 kg. Coefficient of friction = 0.7 Force(Vertical and Horizontal) = mass x gravity x (u x cos(theta) + sin(theta) .(mass = 1 kg, gravity = 9.81 m/s^2, u = 0.7) Force = 17.50 N Torque = Force x perpendicular distance.(Force = 9.81 N, perpendicular distance = 2.5 cm) Torque = 17.50 x 2.5 = 36.01 N-cm. Torque = 3.67 kg-cm. Torque with (Factor of safety =1.5) = 3.67 x 1.5 = 5.50 kg-cm..

Adapter selection:. ADAPTER SELECTION: For DC motor(Belt drive): Stepper motor of operating voltage 12V. Nominal current = 300mA. Number of motors =2. Total current = number of motors x 300mA = 2 x 300mA = 0.6A. Total Current with (FOS = Factor of safety = 1.2) = 0.6 x 1.2 = 0.72A. So the adapter required for the following is 12V of 1A. For stepper motor(Conveyer belt) Stepper motor of operating voltage 5V. Nominal current = 300mA = 0.3A. Total current = 300mA = 0.3A. Total Current with (FOS = Factor of safety = 1.2) = 0.3 x 1.2 = 0.36A. So the adapter required for the following is 5V of 1A. For servo motor(Rack and Pinion): Servo motor of operating voltage 5V. Nominal current = 250mA. Total Current = 250mA. Total Current with (FOS = Factor of safety = 1.2)= 300mA. So the adapter required for the following is 5V of 1A. Therefore in conclusion a 12V,1A and a 5V,1A adapters are required..