In this presentation, we will explore the value of 'a' needed to satisfy an equation. We'll do this by integrating 1 divided by x into the square root of one minus x cube. This equation can be expressed as the log of one minus x cube, divided by the square root of one minus x cube plus one, plus 'b.' To find the value of 'a' that satisfies the equation, we will solve for the log, plus 'b.' With this, we can see that 'a' equals... Let's get started and explore this equation together..
so here we will multiply and divide x square to the left hand side and then assume one minus x cube as t square
a log. + b.