Pre-Calculus

Pre-Calculus.

T he distance of a line segment.. If a line segment has coordinates (2, –3) and (–1, –2). Find the length of line segment. Therefore , by distance formula , = √ (X 2 -X 1 ) 2 +(-Y 2 –Y 1 )) 2 = √ (2-(-1)) 2 +(-3 –(-2)) 2 = √ (2+1)) 2 +(-3+2)) 2 = √ (3) 2 +(–1) 2 = √ (3) 2 + (–1) 2 = √ 9+1 = √10 or approximately 3.16.

Calculating the midpoint of a line segment. What is the midpoint between the points (2, 6) and (8, 12 )? We use the coordinates given in the midpoint formula: M =((x1+x2)/2,(y1+y2)/2) = [(2+8)/2), (6 + 12)/ 2] = [10/2. 18/2] = [5, 9] The coordinates of the midpoint are M = [5,9].

Calculating the Slope Intercept. Find the equation of the straight line that has slope m = 3 and passes through the point (–2, –5 ). Given , m = 3 As per the given point, we have; y = -5 and x = -2 Hence , putting the values in the above equation, we get; - 5 = 3(-2) + c - 5 = -6+c c = -5 + 6 = 1 Hence , the required equation will be; y = 3x+1.

Graph lines using the slope-intercept. Graph the line below using its slope and y-intercept. y = -3/4 – 2 Compare y = mx + b to the given equation y =x - 2. Clearly, we can identify both the slope intercept. The y-intercept is simply b = - 2 or ( 0,2) while the slope is m =..

Calculating the value of trigonometric functions using the trigonometric identities..

Converting radian to degrees, degrees to radian..

Solving arc length problems using radian measure..

Converting 45 degrees to radians. Converting 45 degrees to radians.