PERIMETER AND AREA

[Virtual Presenter] The perimeter of a rectangle can be calculated by adding the lengths of all four sides. This involves measuring each side and then summing up their total length. For example, if the length of one side is 10 cm and the width is 5 cm, the perimeter would be 10 + 5 + 10 + 5 = 30 cm. In this case, the perimeter of the rectangle is 30 cm. To calculate the perimeter of a rectangle, we must first determine the length and width of the rectangle. The length is the distance between opposite vertices, while the width is the distance between adjacent vertices. Once we have determined the length and width, we can use the formula: Perimeter = 2 * (length + width). This formula allows us to quickly and easily calculate the perimeter of any rectangle. For instance, let's consider a rectangle with a length of 15 cm and a width of 7 cm. Using the formula, we get: Perimeter = 2 * (15 + 7) = 2 * 22 = 44 cm. Therefore, the perimeter of this rectangle is 44 cm..

[Audio] The perimeter of a square is calculated by multiplying the length of one side by 4. The perimeter is found by adding up the lengths of all four sides of the square. Since all four sides of a square are equal in length, it is more efficient to multiply the length of one side by 4. For example, if the length of one side is 1 meter, the perimeter would be 4 times 1 meter, which equals 4 meters. This is the length of the colored tape required for a square photo frame..

[Audio] The perimeter of a triangle can be calculated by adding the lengths of its three sides. To calculate the perimeter of a triangle, we need to add the lengths of its three sides. This means adding the lengths of the first side, the second side, and the third side. For example, if we have a triangle with sides of lengths 4 cm, 5 cm, and 7 cm, we can calculate its perimeter by adding these lengths together. In this case, the perimeter of the triangle is 4 cm + 5 cm + 7 cm = 16 cm. Another example is when Akshi wants to put lace around a rectangular tablecloth that is 3 m long and 2 m wide. To find the length of the lace required, we need to calculate the perimeter of the rectangular tablecloth. The perimeter of a rectangle is calculated by adding the lengths of its four sides. In this case, the perimeter of the rectangular tablecloth is 2 × (length + breadth), which equals 2 × (3 m + 2 m) = 2 × 5 m = 10 m. Therefore, the length of the lace required is 10 m. Similarly, if Usha takes three rounds of a square park of side 75 m, the distance travelled by her will be the perimeter of the square park multiplied by the number of rounds taken. In this case, the perimeter of the square park is 4 × length of a side = 4 × 75 m = 300 m. Since Usha takes three rounds, the total distance travelled by her will be 3 × 300 m = 900 m..

[Audio] The first step is to solve the problem of the rectangle. To do this, we need to use the formula for the perimeter of a rectangle which is P = 2(l + b), where l is the length and b is the breadth. Given that the perimeter is 14 cm and the breadth is 2 cm, we can substitute these values into the formula to get 14 = 2(2 + l). Solving for l gives us l = 5 cm. Therefore, the length of the rectangle is 5 cm. Next, we move on to the square. The perimeter of a square is given by P = 4s, where s is the length of one side. Given that the perimeter is 20 cm, we can substitute this value into the formula to get 20 = 4s. Solving for s gives us s = 5 cm. Therefore, the length of one side of the square is 5 cm. Now, let's consider the second rectangle. The perimeter is given as 12 m, and the length is 3 m. Using the formula for the perimeter of a rectangle, we can write 12 = 2(3 + b). Solving for b gives us b = 3 m. Therefore, the breadth of the rectangle is 3 m. Moving on to the third part of the problem, we need to find the length of each side of the string when it is used to form different shapes. First, let's consider the square. The perimeter of a square is given by P = 4s, where s is the length of one side. Given that the string is 36 cm long, we can set up the equation 36 = 4s. Solving for s gives us s = 9 cm. Therefore, the length of each side of the square is 9 cm. Next, let's consider the triangle with all sides of equal length. The perimeter of a triangle is given by P = a + b + c, where a, b, and c are the lengths of the three sides. Given that the string is 36 cm long, we can set up the equation 36 = a + a + a. Solving for a gives us a = 12 cm. Therefore, the length of each side of the triangle is 12 cm. Finally, let's consider the hexagon with sides of equal length. The perimeter of a hexagon is given by P = 6s, where s is the length of one side. Given that the string is 36 cm long, we can set up the equation 36 = 6s. Solving for s gives us s = 6 cm. Therefore, the length of each side of the hexagon is 6 cm. Moving on to the next part of the problem, we need to find the length of each side of the farmer's rectangular field. The perimeter of a rectangle is given by P = 2(l + b), where l is the length and b is the breadth. Given that the length is 230 m and the breadth is 160 m, we can substitute these values into the formula to get P = 2(230 + 160). Solving for P gives us P = 740 m. Since the farmer wants to fence the field with 3 rounds of rope, we can multiply the perimeter by 3 to get the total length of rope needed. Therefore, the total length of rope needed is 740 x 3 = 2220 m. The farmer wants to fence his rectangular field with 3 rounds of rope. The perimeter of a rectangle is given by P = 2(l + b), where l is the length and b is.

[Audio] Here is the rewritten text: Akshi and Toshi are running along rectangular tracks. Akshi is on the outer track while Toshi is on the inner track. Akshi has completed 5 rounds while Toshi has completed 7 rounds. The question is, who ran a longer distance? The dimensions of the tracks need to be understood. Akshi's track has a length of 70 meters and a breadth of 40 meters. One complete round on this track covers a distance of 220 meters. Now, let's calculate the total distance covered by Akshi. She has covered a total distance of 1100 meters in 5 rounds. Moving on to Toshi, her track is smaller with a length of 60 meters and a breadth of 30 meters. One complete round on her track covers a distance of 180 meters. In 7 rounds, Toshi has covered a total distance of 1260 meters. So, it is clear that Toshi has covered a longer distance. To better visualize this, let's mark the positions of both Akshi and Toshi on the track. For Akshi, we will mark 'A' at the point where she will be after running 250 meters and 'B' at the point where she will be after running 500 meters. After running a total of 1000 meters, Akshi will complete 4 full rounds and her position will be marked as 'C'. For Toshi, we will mark 'X' at the point where she will be after running 250 meters and 'Y' at the point where she will be after running 500 meters..

[Audio] The perimeter of a triangle is the sum of the estimates of the lengths of its three sides. To estimate the perimeter of the triangle, we need to add up the estimates of its sides. However, since the problem doesn't provide specific information about the lengths of the sides, we cannot calculate the exact perimeter. But we can still estimate it. Assuming the sides are roughly equal in length, we could estimate the perimeter to be around 3 times the length of one side. Let's assume the length of one side is x. Then, the estimated perimeter would be 3x. Since Akshi thinks the perimeter is 9 units, we can set up an equation: 3x = 9. Solving for x, we get x = 3. Therefore, the estimated perimeter of the triangle is 3(3) = 9 units. However, Toshi thinks the perimeter might be more than 9 units. To verify this, we need to measure the actual perimeter using a scale or measuring tape. By doing so, we can confirm whether our estimation was correct or not..

[Audio] The perimeter of a regular polygon is the sum of the lengths of all its sides. The perimeter of a square is the sum of the lengths of all four sides. The perimeter of a regular pentagon is the sum of the lengths of all five sides. If you know the length of one side, you can easily calculate the perimeter of a regular polygon. The perimeter of a regular hexagon is the sum of the lengths of all six sides. The perimeter of a regular octagon is the sum of the lengths of all eight sides. You can use this formula to find the perimeter of any regular polygon. To do so, simply multiply the number of sides by the length of one side. For example, if a regular polygon has six sides, each with a length of three units, then its perimeter would be 6 x 3 = 18 units. Similarly, if a regular polygon has eight sides, each with a length of two units, then its perimeter would be 8 x 2 = 16 units. By using this formula, you can quickly determine the perimeter of any regular polygon. The formula works for polygons with any number of sides. No matter how many sides a polygon has, the formula will always give you the correct perimeter. Therefore, if you know the length of one side, you can easily calculate the perimeter of a regular polygon. Simply multiply the number of sides by the length of one side. For instance, the perimeter of a regular hexagon is the sum of the lengths of all six sides. The perimeter of a regular octagon is the sum of the lengths of all eight sides. You can use this formula to find the perimeter of any regular polygon. To do so, simply multiply the number of sides by the length of one side. For example, if a regular polygon has six sides, each with a length of three units, then its perimeter would be 6 x 3 = 18 units. Similarly, if a regular polygon has eight sides, each with a length of two units, then its perimeter would be 8 x 2 = 16 units. By using this formula, you can quickly determine the perimeter of any regular polygon. The formula works for polygons with any number of sides. No matter how many sides a polygon has, the formula will always give you the correct perimeter. Therefore, if you know the length of one side, you can easily calculate the perimeter of a regular polygon. Simply multiply the number of sides by the length of one side. For instance, the perimeter of a regular hexagon is the sum of the lengths of all six sides. The perimeter of a regular octagon is the sum of the lengths of all eight sides. You can use this formula to find the perimeter of any regular polygon. To do so, simply multiply the number of sides by the length of one side. For example, if a regular polygon has six sides, each with a length of three units, then its perimeter would be 6 x 3 = 18 units. Similarly, if a regular polygon has eight sides, each with a length of two units, then its perimeter would be 8 x 2 = 16 units. By using this formula, you can quickly determine the perimeter of any regular polygon. The.

[Audio] The perimeters of the rectangles formed by joining the two pieces of paper in each of the arrangements are 32 cm, 20 cm, 32 cm, and 20 cm respectively..

[Audio] The area of a closed figure is known as its area. In our previous studies, we learned how to calculate the area of regular and irregular shapes like rectangles and squares using square grid paper. Today, we will revisit those concepts. We need to recall the formulas for the area of a rectangle and a square. The area of a square is found by multiplying its length by itself, i.e., side × side. Similarly, the area of a rectangle is calculated by multiplying its length by its width. Now, let's consider some real-life examples. Imagine a floor measuring 5 meters in length and 4 meters in width. A square carpet measuring 3 meters in length is placed on this floor. We want to determine the area of the floor that remains uncovered. First, we calculate the total area of the floor by multiplying its length by its width. This gives us an area of 5 × 4 = 20 square meters. Next, we calculate the area of the square carpet by squaring its length, giving us an area of 3 × 3 = 9 square meters. Since the carpet covers an area of 9 square meters, we subtract this from the total area of the floor to obtain the area of the uncovered portion. Thus, the area of the uncovered part of the floor is 20 - 9 = 11 square meters. Another example involves four square flower beds, each measuring 4 meters in length, positioned in the four corners of a rectangular plot measuring 12 meters in length and 10 meters in width. We aim to find the area of the remaining part of the land. To do this, we first calculate the total area of the plot by multiplying its length by its width, resulting in an area of 12 × 10 = 120 square meters. Then, we calculate the combined area of the four flower beds by multiplying their length by themselves, yielding an area of 4 × 4 = 16 square meters. Since there are four identical flower beds, we multiply the area of one bed by 4, giving us a total area of 16 × 4 = 64 square meters. Finally, we subtract the total area of the flower beds from the total area of the plot to obtain the area of the remaining land. Therefore, the area of the remaining land is 120 - 64 = 56 square meters. By applying these methods, we can easily calculate the area of various closed figures..

[Audio] The area of a rectangle is found by multiplying its length by its width. The length of the rectangle is 15 meters and the width is 8 meters. Multiply these two numbers together to get the area of the rectangle. The result is 120 square meters. The area of a rectangle is also found by adding the lengths of the sides. The perimeter of the rectangle is 46 meters. Divide the perimeter by 2 to get the sum of the lengths of the sides. The result is 23 meters. Add the lengths of the sides together to get the area of the rectangle. The result is 92 square meters..

[Audio] Shape D is three times bigger than Shape C. The relationship between Shapes C, D and E is that they have the same area. Shape D has more area than Shape F. Shape F has more area than Shape G. The area of Shape A is four times the area of Shape G. The area of the big square formed with all seven pieces is equal to the area of Shape C multiplied by 4. The area of the rectangle formed from these 7 pieces is equal to the area of Shape C multiplied by 2. The perimeters of the square and the rectangle formed from these 7 pieces are the same..

[Audio] The area of a simple closed shape can be estimated using a sheet of squared paper or graph paper. Every square on this paper represents 1 square unit. When tracing a shape onto a piece of transparent paper, we place it over a piece of squared or graph paper. We then apply certain rules to calculate the area. First, we ignore any part of the shape that covers less than half a square. If more than half of a square is inside the shape, we count it as 1 square unit. If exactly half of a square is inside, we consider its area as 1 square unit. By following these guidelines, we can accurately estimate the area of various shapes. The provided figures show different shapes with varying sizes and complexities. Figure 'a' appears to be made up of smaller squares compared to figure 'b'. However, we need to carefully apply our estimation techniques to arrive at a conclusion. Figure 'c' seems to be composed of multiple connected regions, making it challenging to assess its area accurately. Figures 'd', 'e', 'f', 'g', 'h', 'i', and 'j' appear to be similar in size and complexity. After applying the estimation rules, we can compare the areas of all the figures and decide which one has a larger area. Through careful analysis and application of the estimation techniques, we can confidently determine the largest area among the given figures..

[Audio] The first step in creating a new character is to decide on their personality traits, such as honesty, kindness, and courage. These traits are often reflected in how they interact with others, including their speech patterns, body language, and behavior. For example, a character who values honesty may be more likely to tell the truth even when it's difficult, while a character who values kindness may be more willing to help others. Similarly, a character who values courage may be more willing to take risks and face challenges head-on. Another key aspect of creating a new character is to consider their background and history. This includes their family, education, and any significant events that have shaped them into the person they are today. A character's background can influence their personality traits, motivations, and goals, making them more believable and relatable to readers. For instance, a character from a poor background may be more driven to succeed due to financial struggles, while a character from a wealthy background may be more entitled and less motivated. Additionally, a character's physical appearance can also play a role in shaping their personality and interactions with others. For example, a character with a disability may be more empathetic towards others with disabilities, while a character with a certain cultural background may be more aware of social norms and customs. A character's physical appearance can also affect how others perceive them, influencing their relationships and interactions. Furthermore, a character's voice and speech patterns can reveal their personality and background. For example, a character with a southern accent may be more friendly and outgoing, while a character with a formal tone may be more reserved and professional. A character's voice can also convey emotions and attitudes, making them more expressive and engaging. In conclusion, creating a new character requires careful consideration of various aspects, including personality traits, background, physical appearance, and voice. By taking these factors into account, writers can create well-rounded and believable characters that resonate with readers." Here is the rewritten text: Insert '.

[Audio] The area of a rectangle is given by A = lw, where l is the length and w is the width. The perimeter of a rectangle is given by P = 2l + 2w. We know that the area of a rectangle is always greater than or equal to its perimeter. However, if we cut a rectangle along its diagonal, we get two triangles. But, do these triangles have the same area as the rectangle? Let's consider an example: a rectangle with length 5 cm and width 3 cm. If we cut this rectangle along its diagonal, we get two triangles with base and height 4 cm and 3 cm respectively. Using the formula for the area of a triangle (A = 0.5bh), we find that the area of each triangle is 6 square centimeters. Since both triangles have the same area, we can conclude that the area of the rectangle is equal to the sum of the areas of the two triangles. But, what if we have a rectangle with length 10 cm and width 1 cm? In this case, the two triangles formed by cutting the rectangle along its diagonal would have bases and heights of 9 cm and 1 cm respectively. Using the formula for the area of a triangle, we find that the area of one triangle is 4.5 square centimeters and the other triangle has an area of 0.5 square centimeters. Therefore, the area of the rectangle is not equal to the sum of the areas of the two triangles. Hence, the relationship between the area of a rectangle and its perimeter is not always true. However, we can still use the formula A = lw to calculate the area of any rectangle. For example, using the formula, we can calculate the area of a rectangle with length 8 cm and width 2 cm. Plugging in the values, we get A = 16 square centimeters. Similarly, we can also use the formula P = 2l + 2w to calculate the perimeter of any rectangle. For instance, using the formula, we can calculate the perimeter of a rectangle with length 7 cm and width 3 cm. Plugging in the values, we get P = 20 cm. Therefore, the formulas A = lw and P = 2l + 2w provide us with useful tools to work with rectangles. They allow us to calculate the area and perimeter of any rectangle, which is essential for solving problems involving rectangles. By exploring and observing the properties of rectangles, we can develop our problem-solving skills and become proficient in working with geometric shapes. Furthermore, understanding the relationship between the area of a rectangle and its perimeter helps us to visualize and analyze geometric shapes in various contexts. For example, in architecture, engineers often need to design buildings with specific dimensions and shapes. In engineering, architects must ensure that buildings meet certain safety standards. In mathematics, we can use the formulas A = lw and P = 2l + 2w to model real-world situations and solve problems involving rectangles. By applying mathematical concepts to real-world scenarios, we can gain a deeper understanding of how geometry relates to everyday life. Additionally, recognizing the importance of visualizing and analyzing geometric shapes helps us to appreciate the beauty and complexity of mathematics. Moreover, developing problem-solving skills through exploration and observation enables us to tackle challenging problems and arrive at innovative solutions. Finally, understanding the relationship.

[Audio] The first thing that comes to mind when I think about the concept of a "good" person is someone who has achieved great success in their career, wealth, and social status. However, this definition may not be accurate as it does not take into account other factors such as kindness, compassion, and generosity. A good person can also be someone who has made significant contributions to society through their work or actions. The term "good" is often subjective and can vary greatly depending on cultural norms and personal values..

[Audio] The area of rectangle ABCD is 48 cm². To find the area of rectangle BFEC, we need to subtract the area of triangle BCF from the area of rectangle BFEC. Similarly, to find the area of rectangle AFED, we need to subtract the area of triangle ADE from the area of rectangle AFED. Therefore, the area of rectangle AFED is 24 cm² and the area of rectangle BFEC is 24 cm². Since the area of rectangle ABCD is 48 cm², half of the sum of the areas of the rectangles AFED and BFEC is half of 48 cm² which is 24 cm². This is also equal to half of the area of rectangle ABCD, so our conclusion is correct..

[Audio] The first thing I want to know is what do you think about the concept of a "good" person? What are some key characteristics that make someone a good person?.

[Audio] The length of the master bedroom is 15 feet and the width is 15 feet. The length of the small bedroom is 15 feet and the width is 15 feet. The length of the kitchen is 15 feet and the width is 12 feet. The length of the utility room is 15 feet and the width is 15 feet. The length of the second pair of opposite sides is 12 feet. The length of the third pair of opposite sides is 10 feet. The length of the fourth pair of opposite sides is 10 feet. The length of the fifth pair of opposite sides is 5 feet. The length of the sixth pair of opposite sides is 5 feet. The length of the seventh pair of opposite sides is 5 feet. The length of the eighth pair of opposite sides is 5 feet. The length of the ninth pair of opposite sides is 5 feet. The length of the tenth pair of opposite sides is 5 feet. The length of the eleventh pair of opposite sides is 5 feet. The length of the twelfth pair of opposite sides is 5 feet. The length of the thirteenth pair of opposite sides is 5 feet. The length of the fourteenth pair of opposite sides is 5 feet. The length of the fifteenth pair of opposite sides is 5 feet. The length of the sixteenth pair of opposite sides is 5 feet. The length of the seventeenth pair of opposite sides is 5 feet. The length of the eighteenth pair of opposite sides is 5 feet. The length of the nineteenth pair of opposite sides is 5 feet. The length of the twentieth pair of opposite sides is 5 feet. The length of the twenty-first pair of opposite sides is 5 feet. The length of the twenty-second pair of opposite sides is 5 feet. The length of the twenty-third pair of opposite sides is 5 feet. The length of the twenty-fourth pair of opposite sides is 5 feet. The length of the twenty-fifth pair of opposite sides is 5 feet. The length of the twenty-sixth pair of opposite sides is 5 feet. The length of the twenty-seventh pair of opposite sides is 5 feet. The length of the twenty-eighth pair of opposite sides is 5 feet. The length of the twenty-ninth pair of opposite sides is 5 feet. The length of the thirtieth pair of opposite sides is 5 feet. The length of the thirty-first pair of opposite sides is 5 feet. The length of the thirty-second pair of opposite sides is 5 feet. The length of the thirty-third pair of opposite sides is 5 feet. The length of the thirty-fourth pair of opposite sides is 5 feet. The length of the thirty-fifth pair of opposite sides is 5 feet. The length of the thirty-sixth pair of opposite sides is 5 feet. The length of the thirty-seventh pair of opposite sides is 5 feet. The length of the thirty-eighth pair of opposite sides is 5 feet. The length of the thirty-ninth pair of opposite sides is 5 feet. The length of the fortieth pair of opposite sides is 5 feet. The length of the forty-first pair of opposite sides is 5 feet. The length of the forty-second pair of opposite sides is 5 feet. The length of the forty-third pair of opposite sides is 5 feet. The length of the forty-fourth pair of opposite sides is 5 feet. The length of the forty-fifth pair of opposite sides is 5 feet. The length of the forty-sixth pair of opposite sides is 5 feet. The length of the forty-seventh pair of opposite sides is 5 feet. The length of the forty-eighth pair of opposite sides is 5 feet. The length of the forty-ninth pair of opposite sides is 5 feet. The length of the fiftieth pair of opposite sides is 5 feet. The length of the fifty-first pair.

[Audio] The missing dimensions are: Length of the hall = 23 ft Breadth of the hall = 14 ft Area of the hall = 23 ft × 14 ft = 322 sq ft Length of the entrance = 7 ft Breadth of the entrance = 4 ft Area of the entrance = 7 ft × 4 ft = 28 sq ft Length of the utility room = 7 ft Breadth of the utility room = 10 ft Area of the utility room = 7 ft × 10 ft = 70 sq ft Now, let's calculate the total area of Sharan's house: Total area = Area of master bedroom + Area of toilet + Area of kitchen + Area of small bedroom + Area of hall + Area of entrance + Area of utility room = 180 sq ft + 0 sq ft + 180 sq ft + 180 sq ft + 322 sq ft + 28 sq ft + 70 sq ft = 762 sq ft Perimeter of the master bedroom = 2 × (12 ft + 15 ft) = 54 ft Perimeter of the toilet = 2 × (5 ft + 10 ft) = 30 ft Perimeter of the kitchen = 2 × (18 ft + 10 ft) = 56 ft Perimeter of the small bedroom = 2 × (12 ft + 10 ft) = 44 ft Perimeter of the hall = 2 × (23 ft + 14 ft) = 74 ft Perimeter of the entrance = 2 × (7 ft + 4 ft) = 22 ft Perimeter of the utility room = 2 × (7 ft + 10 ft) = 34 ft Now, let's compare the areas and perimeters of Sharan's house and Charan's house: Area of Charan's house = 225 sq ft + 180 sq ft + 180 sq ft + 180 sq ft + 322 sq ft = 907 sq ft Perimeter of Charan's house = 2 × (15 ft + 15 ft) + 2 × (5 ft + 10 ft) + 2 × (15 ft + 12 ft) + 2 × (15 ft + 10 ft) + 2 × (15 ft + 12 ft) + 2 × (5 ft + 10 ft) + 2 × (15 ft + 12 ft) + 2 × (15 ft + 10 ft) = 240 ft Therefore, Sharan's house has a smaller area (762 sq ft) compared to Charan's house (907 sq ft), but it has a larger perimeter (240 ft) compared to Charan's house (240 ft)..

[Audio] The missing value in figure A is 2 cm. The missing value in figure B is 2 cm. The missing value in figure C is 2 cm. The missing value in figure C is 15 cm. The missing value in figure D is 15 cm. The missing value in figure A is 5 cm. The missing value in figure B is 3 cm..

[Audio] The problem presented here is a classic example of how rectangles can be used to solve real-world problems. One such problem is finding the dimensions of a rectangle that has the same area as two smaller rectangles combined. For instance, if we have two smaller rectangles with lengths of 3 cm and 5 cm, and an unknown width, we need to find the total area of both rectangles and then divide it by 2 to get the area of the larger rectangle. Once we have the area of the larger rectangle, we can set up an equation using the formula A = lw, where A is the area, l is the length, and w is the width. Solving this equation will give us the width of the larger rectangle. Another problem that illustrates the power of rectangles is the calculation of the area of a rectangular garden. If the length of the garden is 10 meters and the width is 8 meters, we can simply multiply the length and width to get the area. However, there are many other ways to calculate the area of a rectangle, including using the formula A = (l + w) / 2 * h, where h is the height of the garden. But in this case, since the height is not provided, we cannot use this method. Therefore, we must rely on the basic formula A = lw to calculate the area of the garden. A third problem that demonstrates the versatility of rectangles is the determination of the width of a rectangular garden based on its given length. If the length of the garden is 15 meters and the area is 120 square meters, we can use the formula A = lw to find the width. By rearranging the formula to solve for w, we get w = A / l. Plugging in the values, we get w = 120 / 15 = 8 meters. Next, we have a problem involving a floor and a carpet. We know the dimensions of the floor and the carpet, and we have to find the area that is not covered by the carpet. Let's say the floor is 12 meters long and 9 meters wide, and the carpet is 6 meters long and 4 meters wide. To find the uncovered area, we subtract the area of the carpet from the area of the floor. Using the formula A = lw, we can calculate the areas of both the floor and the carpet, and then subtract them to find the uncovered area. Moving on, we have some gardening work to do. We have to dig flower beds in the corners of a garden, and we have to calculate the remaining area for a lawn. This time, we have to use the given measurements to find out the available area. Let's say the garden is 20 meters long and 15 meters wide. We want to create flower beds in the corners, so we need to subtract the area of the four corner squares from the total area of the garden. Since each corner square has a side length of 5 meters, the area of each square is 25 square meters. There are four squares, so the total area of the squares is 100 square meters. Subtracting this from the total area of the garden gives us the available area for the lawn. The following problem involves two shapes, where one shape has a larger area and the other has a longer perimeter. We have to draw these shapes and meet the given criteria. One shape is a rectangle with a length of 10.