UNDERSTANDING. DILUTION. I. II. III. IV.
THE CONCEPT. I. II. III. IV.
FORMULAS. I. II. III. IV.
WORD PROBLEMS. I. II. III. IV.
PRACTICE. I. THE CONCEPT. II. FORMULAS. III. WORD PROBLEMS.
I. THE CONCEPT. stocK.
solute. Solvent. 200 400 800 600 1000. STOCK. APPROXIMATE VOLUMES.
STOCK.
[image]. STOCK. Solvent. 200 400 800 600 1000.
Diluted solution. 200 400 800 600 1000. STOCK. Solvent.
concentration. =. amount of solute. volume of solution.
c1. V1. I. c2. FORMULAS. V2. II. FORMULAS.
STOCK. [image]. c1. Solution 1. c1. V1. V2. c2. V1.
c1V1 = c2V2. c1. V1. =. c2. V2. c1. V1. c1. x. =.
c1V1 = c2V2. c1V1. =. c2V2. c1. c1. V1. c1V1 = c2V2.
Note: in math. If a = b, then b = a. =. c2V2. c2V2 = c1V1.
I. II. III. WORD PROBLEMS.
10 STEPS TO SOLVING WORD PROBLEMS.
10 STEPS TO SOLVING WORD PROBLEMS Circle all numbers and units in problem; underline the unknown. List numbers with units. Place an “=” sign to the left of each. Write the symbol for the variable to the left of the “=” sign. Determine the unknown. Write down its symbol, then “=” sign, then “?” mark. In parentheses, write the specific unit as indicated in the problem. Check units. Make necessary conversions. Write original formula. Manipulate formula by placing unknown on the left hand side of the equation. (Use triangle if necessary.) 9. Plug in numbers and units; cancel where necessary. 10. Solve. Circle final answer..
CONCENTRATED SOLUTION 500 500 mi 30 200 100 DILUTE SOLUTION 500 mi 100.
1 0 STEPS TO SOLVING WORD PROBLEMS 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. Circle all numbers and units in problem; underline the unknown. List numbers with units. Place an "=" sign to the left of each. Write the symbol for the variable to the left of the "=" sign. Determine the unknown. Write down its symbol, then "=" sign, then "?" mark. In parentheses, write the specific unit as indicated in the problem. Check units. Make necessary conversions. Write original formula. Manipulate formula by placing unknown on the left hand side of the equation. (Use triangle if necessary.) Plug in numbers and units; cancel where necessary. Solve. Circle final answer..
Problem 1.
In a clean beaker you pour 400 mL of the 50 g/L solution that you have prepared and you add enough water to make a 500-mL solution. What is the concentration of your second solution?.
1 0 STEPS TO SOLVING WORD PROBLEMS 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. Circle all numbers and units in problem; underline the unknown. List numbers with units. Place an sign to the left of each. Write the symbol for the variable to the left of the sign. Determine the unknown. Write down its symbol, then "=" sign, then "?" mark. In parentheses, write the specific unit as indicated in the problem. Check units. Make necessary conversions. Write original formula. Manipulate formula by placing unknown on the left hand side of the equation. (Use triangle if necessary.) Plug in numbers and units; cancel where necessary. Solve. Circle final answer..
= 400 mL. = 50 g/L. = 500 mL. Solution. V = 400 mL Solution.
= 500 mL. = ?. 1. = 400 mL. = 50 g/L. 1. 2. 2. Solution.
:-) … Más. YAY!!!!!.
Problem 2.
In a clean beaker you pour 400 mL of a stock solution and you add enough water to make a 500-mL solution whose concentration is 40 g/L. What is the concentration of your stock solution?.
c1V1. c2V2. =. c2 V2. =. c1 x V1. c2. V2. c1. x. V1.
Problem 3.
You want to prepare 500 mL of a 40 g/L solution from a 50 g/L stock solution. What volume of the stock solution would you need to use?.
c1V1. c2V2. =. c2 V2. =. c1 x V1. c2. V2. c1. x. V1.
1 V. You want to prepare 500 mL of a 40 g/L solution from a 50 g/L stock solution. What volume of the stock solution would you need to use?.
Water. Solution 2.
Solution. Diluted solution. c1V1 = c2V2. V2. [image] Solution I.
c1 V1 = c2 V2. V2 = V1 + Vw. c1 V1 = c2 x (V1 + Vw).
c1 V1 = c2 x (V1 + Vw). c1V1. c2. x. ( V1 + Vw). V1.
Problem 4.
How much water do you need to add to 400 mL of a 50 g/L solution to make a solution whose concentration is 40 g/L ?.
c1V1. =. How much water do you need to add to 400 mL of a 50 g/L solution to make a solution whose concentration is 40 g/L ?.
How much water do you need to add to 400 mL of a 50 g/L solution to make a solution whose concentration is 40 g/L ?.
Problem 5.
You add 100 mL of water to 400 mL of a solution whose concentration is 50 g/L. What is the concentration of your final solution?.
c1V1. =. You add 100 mL of water to 400 mL of a solution whose concentration is 50 g/L. What is the concentration of your final solution?.
∴. V. You add 100 mL of water to 400 mL of a solution whose concentration is 50 g/L. What is the concentration of your final solution?.
Can I try now?!.
I. II. III. IV. PRACTICE.
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Practice 1. Image result for yellow push button. Big Dome Pushbutton - Green (Economy) - COM-11961 - SparkFun ....