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Scene 1 (0s)

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S 3:20 :u-lJ 0.

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0 oso— (0 oso) — P -0 0 Ills • = ooso 1 = 0 tus .1 M-m-oJ.

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(k 29 h = r\big(\csc\theta - I\big). • y,) J.CJt satellite s.

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JAiJl JJ! r + h . s—p-o • .sin O — 1 .2 .cscO — sin 9 0 4.3 sino _.

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sin r 1 csc O = sin 9 ¯ r csc 9 r + h. h r cscO —r r(cscO — 1). h r(cscO — I).

Scene 9 (1m 1s)

Height of Satellite Above Earth's Surface 0 h = r (sec0—1) The height h of a satellite above Earth's surface can be determined using the angle between the satellite and the center of the Earth and the radius r of the Earth..

Scene 10 (1m 14s)

— rd (csc9 — 30 .h csc0 r 6371 O 6 13 (csc O) — csc O cot 9 coso • 1 cot 9 csc sin f) sin — —r csc0cot0. .2 =\frac{\sqr.

Scene 11 (1m 25s)

6 csc \cot!\left(\frac =\frac/2}=\sqrt. X 3:33 2. dh r = -2vÆ3r. = 6371 8.0 .4 dh dh — 20 x 6371 -22069.79 dh = -2v/Sr —22069.79 = —r csc ).A.Å.II h.

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31 3x-1 3X+1 9111 4- 1 n + 19 (3x - + 1) 9T2 e..i.3 9 —1. .2 1 0.

Scene 13 (1m 50s)

(3r — + 1) = 9x2 1 f ( — — Ida: — f 2—1 _ 9r2 —1. .2 .3 .4 21) - Ask ChatGP1i.

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9 f 9 In l:rl, 1 1 f (a:) 9111 Irl + C, — 9 + 2-5 13! f(x) 9 In -F -F C, 0..

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2 E=mc2 P(AIB) 10b x 2 ab.

Scene 18 (2m 30s)

2 بﯾوﺑﺗﻟا ﺔﻣﻼﻋ.